A weightless ladder, 20 ft long rests against a frictionless wall at an angle of 60 0 with the horizontal. A 150-pound man is 4 ft from the top of the ladder. A horizontal force is needed to prevent it from slipping. Choose the correct magnitude from the following
Text Solution
Verified by ExpertsThe correct answer is:
C
: Since the system is in equilibrium therefore 
and 
and 
Now by taking the moment of forces about point B.
[from the figure EC= 4 cos 60]
∴ ∴ 
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
If a bullet of mass 5 gm moving with velocity 100 m /sec, penetrates the wooden block up to 6 cm. T…
A force of 100 dynes acts on mass of 5 gm for 10 sec. The velocity produced is
An object will continue moving uniformly until
A diwali rocket is ejecting 0.05 kg of gases per second at a velocity of 400 m/sec. The acceleratin…
A body of mass 2 kg moving on a horizontal surface with an initial velocity of 4 m/sec comes to res…
A body of mass 2 kg is hung on a spring balance mounted vertically in a lift. If the lift descends …